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ONT Re: Information = Comprehension x Extension -- Discussion




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ICE.  Discussion Note 5

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AK = Antti Karttunen
JA = Jon Awbrey

AK: Then, interpreting this:

CSP: | Thus suppose a blind man to be told that
     | no red things are blue.  He has previously
     | known only that red is a color;  and that
     | certain things 'A', 'B', and 'C' are red.
     |
     |    The comprehension of red then has been for him  'color'.
     |    Its extension has been                          'A', 'B', 'C'.
     |
     | But when he learns that no red thing is blue,
     | 'non-blue' is added to the comprehension of red,
     | without the least diminution of its extension.
     |
     |    Its comprehension becomes   'non-blue color'.
     |    Its extension remains       'A', 'B', 'C'.
     |
     | Suppose afterwards he learns that a fourth thing 'D' is red.
     | Then, the comprehension of 'red' remains unchanged, 'non-blue color';
     | while its extension becomes 'A', 'B', 'C', and 'D'.  Thus, the rule
     | that the greater the extension of a term the less its comprehension
     | and 'vice versa', holds good only so long as our knowledge is not
     | added to;  but as soon as our knowledge is increased, either the
     | comprehension or extension of that term which the new information
     | concerns is increased without a corresponding decrease of the other
     | quantity.
     |
     | The reason why this takes place is worthy of notice.  Every addition to
     | the information which is incased in a term, results in making some term
     | equivalent to that term.  Thus when the blind man learns that 'red' is
     | not-blue, 'red not-blue' becomes for him equivalent to 'red'.  Before
     | that, he might have thought that 'red not-blue' was a little more
     | restricted term than 'red', and therefore it was so to him, but
     | the new information makes it the exact equivalent of red.
     | In the same way, when he learns that 'D' is red, the
     | term 'D-like red' becomes equivalent to 'red'.

let's try to cast this within a finite universe of discourse X.

   X  =  {1, 2, 3, 4, 5, 6}.

a predicate p on X is a function p : X -> B = {0, 1} = {false, true}.

therefore, the lattice of possible predicates on X
and the lattice of subsets of X are the same thing.

we could interpret "color" as a higher order predicate,
that is, color : (X -> B) -> B, where color(p) is true
if p : X -> B is color predicate, and false otherwise.

or we could interpret color as an ordinary predicate,
c : X -> B, understood as "things that have color".
then the statement "red is a color" can be read
as the simple implication "red => color".

i can't tell yet whether Peirce's example depends
critically on one interpretation or the other,
so let's try the simpler alternative first.

we start with a "state of information" (SOI)
that 1, 2, 3 are Red, and that Red => Color.

     Color
       |
       |
       |
      Red
      /|\
     / | \
    /  |  \
   1   2   3

next we are told that "no red thing is blue",
which we may formulate without quantifiers as
the proposition (Red Blue), or ~[Red & Blue].

               X = (Red Blue)
               o
              / \
     Color   /   \
       |    /     \
       |  (Blue)   \
       |  /         \
       | /           \
       |/             \
      Red            Blue
      /|\             .
     / | \           .
    /  |  \         .
   1   2   3       .
            .     .
             .   .
              . .
               o
               0 = Red Blue

CSP: | But when he learns that no red thing is blue,
     | 'non-blue' is added to the comprehension of red,
     | without the least diminution of its extension.
     |
     |    Its comprehension becomes   'non-blue color'.
     |    Its extension remains       'A', 'B', 'C'.

next we learn that 4 is Red.

               X = (Red Blue)
               o
              / \
     Color   /   \
       |    /     \
       |  (Blue)   \
       |  /         \
       | /           \
       |/             \
      Red            Blue
      /|\             .
     / | \           .
    /  |  \         .
   1   2 3 4       .
            .     .
             .   .
              . .
               o
               0 = Red Blue

CSP: | Then, the comprehension of 'red' remains unchanged, 'non-blue color';
     | while its extension becomes 'A', 'B', 'C', and 'D'.  

AK: So, before knowing the truth about red and non-blue,
    the blind man had a conceptual graph something like this:

                              color
                               / \
                              /   \
                             /    non-blue
                            /     /
                           red   /
                            \   /
                             \ /
                             non-blue red

AK: But after it, the lattice changes to:

                             color
                              | \
                              |  \
                              |  non-blue
                              |  /
                              | /
                              |/
                              red (= non-blue red),

yes, this seems to be basically the same thing as what i got.

AK: As an arrow is added between non-blue and red,
    and thus the "non-blue red" = glb(red, non_blue)
    happens to be red itself.

you can think of this as a quotient operation on lattices.
starting with the unconstrained power set lattice, imposing
a constraint then acts to identify nodes previously distinct.
i have worked out some examples like this that i will look up.

but i am forced to interrupret the continuum of discourse hic et nunc ...

jon awbrey

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http://www.cs.bsu.edu/homepages/mighty/history.html
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