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ONT Re: Model Theory




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Note 17

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| 1.  Introduction
|
| 1.2.  Model Theory for Sentential Logic (cont.)
|
| 1.2.18.  Theorem.
|
|          1.  A theory !C! is preserved under intersections
|              if and only if !C! has a set of conditional axioms.
|
|          2.  A sentence p is preserved under intersections
|              if and only if p is equivalent to a conditional sentence.
|
| Proof.   1.  We leave to the reader the proof that every conditional
|              sentence (and hence every set of conditional sentences)
|              is preserved under intersections.
|
|              Conversely, let !C! be preserved under intersections.
|              Consider the set !D! of all conditional consequences
|              of !C!.  It suffices to show that every model of !D!
|              is a model !C!.   Let B be an arbitrary model of !D!.
|              For each T in $S$ - B, let !S!_T be the set of all
|              sentences of the form
|
|              S_1  &  ...  &  S_k  &  ~T
|
|              which hold in B.  We also let the sentence ~T itself be
|              in !S!_T.  We first note that the conjunction of finitely
|              many sentences in !S!_T is again equivalent to a sentence
|              in !S!_T.  Consider a sentence p in !S!_T.  Then ~p is
|              clearly equivalent to a conditional sentence q either
|              of the form S or of the form
|
|              ~S_1  v  ...  v  ~S_k  v  T.
|
|              But q fails in B, so q does not belong to !D!.  This means that q,
|              and hence ~p, is not a consequence of !C!,  and it follows that
|              !C! |_| {p} is satisfiable.  Since !S!_T is, up to equivalence,
|              closed under finite conjunction, we see that !C! |_| !S!_T is
|              finitely satisfiable.  Applying the Compactness Theorem, we
|              may choose a model A_T of !C! |_| !S!_T .
|
|              For each T in $S$ - B, we have T not in A_T and B c A_T.
|              Thus, if $S$ - B is not empty, then:
|
|              B  =  |^|_(T not in B) A_T.
|
|              Since each A_T is a model of !C! and !C! is
|              closed under intersections, we have B |= !C!.
|
|              In the remaining case B = $S$, we let !S!
|              be the set of all sentences of the form
|
|              S_1  &  ...  &  S_k.
|
|              Arguing as before, we find that !C! |_| !S!
|              is finitely satisfiable and thus has a model.
|
|              But B is the only model of !S!, so again B is a model of !C!.
|
|              We have now shown that every model of !D! is a model of !C!,
|              and it follows that !D! is a set of conditional axioms for !C!.
|
|          2.  This follows from (1) by an argument
|              similar to the last part of the proof
|              of Theorem 1.2.16.  -|
|
| Chang & Keisler, 'Model Theory', pages 15-16.
|
| C.C. Chang and H.J. Keisler, 'Model Theory',
| North-Holland, Amsterdam, Netherlands, 1973.

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