Thread Links Date Links
Thread Prev Thread Next Thread Index Date Prev Date Next Date Index

ONT Re: Model Theory




¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤

Note 12

¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤

| 1.  Introduction
|
| 1.2.  Model Theory for Sentential Logic (cont.)
|
| 1.2.9.  Lemma.  (Lindenbaum's Theorem).
|
|         Any consistent set !S! of sentences can be enlarged
|         to a maximal consistent set !C! of sentences.
|
| Proof.  Let us arrange all of the sentences of $S$ in a list:
|
|         p_0,  p_1,  p_2,  ...,  p_!a!,  ...
|
|         The order in which we list them is immaterial,
|         as long as the list associates in a one-one
|         fashion an ordinal number with each sentence.
|
|         We shall form an increasing chain
|         of consistent sets of sentences:
|
|         !S!  =  !S!_0  c  !S!_1  c  !S!_2  c  ...  c  !S!_!a!  c  ...
|
|         If !S! |_| {p_0} is consistent, define !S!_1  =  !S! |_| {p_0}.
|
|         Otherwise, define !S!_1  =  !S!.
|
|         At the !a!^th stage, we define:
|
|         1.  !S!_(!a! + 1)  =  !S!_!a! |_| {p_!a!}
|
|             if !S!_!a! |_| {p_!a!} is consistent;
|
|         2.  Otherwise define:
|
|             !S!_(!a! + 1)  =  !S!_!a!.
|
|         At limit ordinals !a! take unions:
|
|         !S!_!a!  =  |_|^(!b! < !a!) !S!_!b!.
|
|         Now let !C! be the union of all the sets !S!_!a!.
|
|         We claim that !C! is consistent.
|
|         Suppose not.
|
|         Then there is a deduction
|
|         q_0,  q_1,  ...,  q_u
|
|         of the sentence S & ~S from !C!, (see Proposition 1.2.8).
|
|         Let r_1, ..., r_v be all the sentences in !C! which are
|         used in this deduction.  We may choose !a! so that all
|         of  r_1, ..., f_v belong to !S!_!a!.  But this means
|         that !S!_!a! is inconsistent (by Proposition 1.2.8),
|         which is a contradiction.
|
|         Having shown that !C! is consistent, we next claim that !C! is
|         maximal consistent.  For suppose !D! is consistent and !C! c !D!.
|         Let p_!a! be in !D!.  Then !S!_!a! |_| {p_!a!} is consistent, hence:
|
|         !S!_(!a! + 1)  =  !S!_!a! |_| {p_!a!}.
|
|         Thus p_!a! is in !C!, and hence !D! = !C!.  -|
|
| Chang & Keisler, 'Model Theory', page 10.
|
| C.C. Chang and H.J. Keisler, 'Model Theory',
| North-Holland, Amsterdam, Netherlands, 1973.

¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤